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copied!<p>You can use the <a href="http://docs.python.org/2/library/decimal.html#decimal.Decimal.normalize" rel="noreferrer"><code>normalize</code></a> method to remove extra precision.</p> <pre><code>>>> print decimal.Decimal('5.500') 5.500 >>> print decimal.Decimal('5.500').normalize() 5.5 </code></pre> <p>To avoid stripping zeros to the left of the decimal point, you could do this:</p> <pre><code>def normalize_fraction(d): normalized = d.normalize() sign, digits, exponent = normalized.as_tuple() if exponent > 0: return decimal.Decimal((sign, digits + (0,) * exponent, 0)) else: return normalized </code></pre> <p>Or more compactly, using <code>quantize</code> as suggested by <a href="https://stackoverflow.com/questions/11227620/drop-trailing-zeros-from-decimal/11227743#comment14749895_11227743">user7116</a>: </p> <pre><code>def normalize_fraction(d): normalized = d.normalize() sign, digit, exponent = normalized.as_tuple() return normalized if exponent <= 0 else normalized.quantize(1) </code></pre> <p>You could also use <code>to_integral()</code> as shown <a href="https://stackoverflow.com/a/18769210/577088">here</a> but I think using <code>as_tuple</code> this way is more self-documenting. </p> <p>I tested these both against a few cases; please leave a comment if you find something that doesn't work. </p> <pre><code>>>> normalize_fraction(decimal.Decimal('55.5')) Decimal('55.5') >>> normalize_fraction(decimal.Decimal('55.500')) Decimal('55.5') >>> normalize_fraction(decimal.Decimal('55500')) Decimal('55500') >>> normalize_fraction(decimal.Decimal('555E2')) Decimal('55500') </code></pre>

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