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PODirectory Name + File Name to Text File
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copied!<p>I have many directories with files in them. I want to create a comma delimited txt file showing directory name, and the files that are within that particular directory, see example below:</p> <p><strong>What I'm looking for:</strong></p> <pre><code>DirName,Filename 999,123.tif 999,1234.tif 999,abc.tif 900,1236.tif 900,xyz.tif ...etc </code></pre> <p>The python code below pushes a list of those file paths into a text file, however I'm unsure of how to format the list as described above.</p> <p><strong>My current code looks like:</strong></p> <p><strong>Update</strong> </p> <p>I've been able to format the text file now, however I'm noticing all the directory names/filenames are not being written to the text file. It is only writing ~4000 of the ~8000 dir/files. Is there some sort limit that I'm reaching with the text file number of rows, the list (mylist) size, or some bad file dir/file character that is stopping it (see updated code below)?</p> <pre><code>from os import listdir from os.path import isfile, join root = r'C:\temp' mylist = ['2'] for path, subdirs, files in os.walk(root): for name in files: mylist.append(os.path.join(path, name)) txt = open(r'C:\temp\output.txt', 'w') txt.write('dir' + ',' + 'file' + '\n') for item in mylist: list = mylist.pop(0) dir, filename = os.path.basename(os.path.dirname(list)), os.path.basename(list) txt.write(dir + ',' + filename + '\n') with open(r'C:\temp\output.txt', 'r') as f: read_data = f.read() </code></pre> <p>Thank You</p>

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