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POHow to use Django views and template tag simultanosly?
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copied!<p>In my Django-template:</p> <pre><code><div class="A"> {% url renders_data object.id %} </div> <div class="B"> {% render_data object.id %} </div> </code></pre> <p>Div <code>A</code> is common way to call a method in <code>views.py</code> whereas Div <code>B</code> is for template tags.</p> <p>User will open a link. Let's say: <code>/myapp/test/</code> a page will open contain two template tag section at the page. Name of this tag is <code>render_data</code> I want to load the data into each template tag with <code>Ajax</code>. To work with it we need <code>request.ajax:</code>. That is why i thought to write views method. I thought to complete it with the following way:</p> <p><li> I wrote the exact copy of <code>template tag</code> in <code>views.py</code> (renders_data with passing object_id parameter) and render it to the right template. When i open the <code>maypp/test</code> after removing the <code>div A</code> from template. It shows the <code>URL</code> (<code>myapp/test/<object_id></code>) in each template tags section (each corner) except the data. Is their any possibility to show the context except this URL <a href="https://dl.dropbox.com/u/21766438/Screenshot%20at%202012-06-19%2001_34_22.png" rel="nofollow">See the image when i choose this option</a></li></p> <p><li> Second i also thought to import views method (<code>renders_data</code>) in template tag (<code>render_data</code>). So that data will display in each corner and <code>request.Ajax:</code> will also work. if this can be possible then how? </li></p> <p>I am not able to solve this issue. please help me :(</p> <p>See how the render_data looks like:</p> <pre><code> @register.simple_tag def render_widget(object_id): from myapp.plugins.model import Widgetsetting widget_setting = Widetsetting.objects.get(id = object_id) widget = widget_settings.get_widget() template_name = widget.template_name context = widget.context(widget=widget_settings) t = get_template("widgets/%s" % template_name) return t.render(Context(context)) </code></pre>

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