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copied!<p>You can create a class that has the character and the frequency as data member, and make the class implements <a href="http://docs.oracle.com/javase/6/docs/api/java/lang/Comparable.html" rel="nofollow"><code>Comparable</code></a> interface.</p> <p>There are 2 options here, you can either:</p> <ul> <li><p>Insert all objects into a class that implements <a href="http://docs.oracle.com/javase/6/docs/api/java/util/List.html" rel="nofollow"><code>List</code></a> interface (e.g. <a href="http://docs.oracle.com/javase/6/docs/api/java/util/ArrayList.html" rel="nofollow"><code>ArrayList</code></a>). Then call <a href="http://docs.oracle.com/javase/6/docs/api/java/util/Collections.html#sort%28java.util.List%29" rel="nofollow"><code>Collections.sort(List<T> list)</code></a> on the <a href="http://docs.oracle.com/javase/6/docs/api/java/util/List.html" rel="nofollow"><code>List</code></a>.</p></li> <li><p>Insert all objects into <a href="http://docs.oracle.com/javase/6/docs/api/java/util/TreeSet.html" rel="nofollow"><code>TreeSet</code></a>. You can obtain the sorted item via <code>iterator()</code>.</p></li> </ul> <p>From the question, it seems that the 2 pieces of data are not members of some existing object in the first place. If any chance that they do, you don't have to create a new class for the character and frequency. You can insert the existing object into a <a href="http://docs.oracle.com/javase/6/docs/api/java/util/List.html" rel="nofollow"><code>List</code></a>, implement a class that extends on <a href="http://docs.oracle.com/javase/6/docs/api/java/util/Comparator.html" rel="nofollow"><code>Comparator</code></a> interface, and sort the <a href="http://docs.oracle.com/javase/6/docs/api/java/util/List.html" rel="nofollow"><code>List</code></a> with <a href="http://docs.oracle.com/javase/6/docs/api/java/util/Collections.html#sort%28java.util.List,%20java.util.Comparator%29" rel="nofollow"><code>Collections.sort(List<T> list, Comparator<? super T> c)</code></a>.</p>

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