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POCounting number of records hour by hour between two dates in oracle
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  1. POCounting number of records hour by hour between two dates in oracle
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    copied!<p>I need a SINGLE query that does this sequence in oracle.</p> <pre><code>select count(*) from table1 where request_time &lt; timestamp'2012-05-19 12:00:00' and (end_time &gt; timestamp'2012-05-19 12:00:00' or end_time=null); select count(*) from table1 where request_time &lt; timestamp'2012-05-19 13:00:00' and (end_time &gt; timestamp'2012-05-19 13:00:00' or end_time=null); select count(*) from table1 where request_time &lt; timestamp'2012-05-19 14:00:00' and (end_time &gt; timestamp'2012-05-19 14:00:00' or end_time=null); select count(*) table1 where request_time &lt; timestamp'2012-05-19 15:00:00' and (end_time &gt; timestamp'2012-05-19 15:00:00' or end_time=null); select count(*) from table1 where request_time &lt; timestamp'2012-05-19 16:00:00' and (end_time &gt; timestamp'2012-05-19 16:00:00' or end_time=null); </code></pre> <p>As you see the hour is increasing one by one. here is the output</p> <pre><code>COUNT(*) 1085 </code></pre> <hr> <pre><code>COUNT(*) 1233 </code></pre> <hr> <pre><code>COUNT(*) 1407 </code></pre> <hr> <pre><code>COUNT(*) 1322 </code></pre> <hr> <pre><code>COUNT(*) 1237 </code></pre> <hr> <p>I have written a query but it does not give me the right answer!</p> <pre><code>select col1, count(*) from (select TO_CHAR(request_time, 'YYYY-MM-DD HH24') as col1 from table1 where request_time &lt;= timestamp'2012-05-19 12:00:00' and (end_time &gt;= timestamp'2012-05-19 12:00:00' or end_time=null)) group by col1 order by col1; </code></pre> <p>this query gives me a result set that sum of it's count(*) is equal to the first query written above! here is the result:</p> <pre><code>COL1 COUNT(*) ------------- ---------------------- 2012-05-19 07 22 2012-05-19 08 141 2012-05-19 09 322 2012-05-19 10 318 2012-05-19 11 282 </code></pre>
 

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