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POInputing characters into arrays in C- follow up
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  1. POInputing characters into arrays in C- follow up
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    copied!<p>This is a follow up question to a previous question I asked about calculating a straight hand..not exactly the same...This is the method to read in cards- it works- but is there a better way- to do this using console input in C ...</p> <pre><code>void read_cards(int num_in_rank[], int num_in_suit[]) { bool card_exists[NUM_RANKS][NUM_SUITS]; char ch, rank_ch, suit_ch; int rank, suit; bool bad_card; int cards_read = 0; for (rank = 0; rank &lt; NUM_RANKS; rank++) { num_in_rank[rank] = 0; for (suit = 0; suit &lt; NUM_SUITS; suit++) card_exists[rank][suit] = false; } for (suit = 0; suit &lt; NUM_SUITS; suit++) num_in_suit[suit] = 0; while (cards_read &lt; NUM_CARDS) { bad_card = false; printf("Enter a card: "); rank_ch = getchar(); switch (rank_ch) { case '0': exit(EXIT_SUCCESS); case '2': rank = 0; break; case '3': rank = 1; break; case '4': rank = 2; break; case '5': rank = 3; break; case '6': rank = 4; break; case '7': rank = 5; break; case '8': rank = 6; break; case '9': rank = 7; break; case 't': case 'T': rank = 8; break; case 'j': case 'J': rank = 9; break; case 'q': case 'Q': rank = 10; break; case 'k': case 'K': rank = 11; break; case 'a': case 'A': rank = 12; break; default: bad_card = true; } suit_ch = getchar(); switch (suit_ch) { case 'c': case 'C': suit = 0; break; case 'd': case 'D': suit = 1; break; case 'h': case 'H': suit = 2; break; case 's': case 'S': suit = 3; break; default: bad_card = true; } while ((ch = getchar()) != '\n') if (ch != ' ') bad_card = true; if (bad_card) printf("Bad card; ignored.\n"); else if (card_exists[rank][suit]) printf("Duplicate card; ignored.\n"); else { num_in_rank[rank]++; num_in_suit[suit]++; card_exists[rank][suit] = true; cards_read++; } } } </code></pre> <p>I know the case statement can have a few optimizations-i.e. using toupper; better representation the card values, etc..Suggestions- please. The code is reflective of C99...</p>
 

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