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copied!<p>Use regex for this. Recursion for trimming a string is really not a good idea:</p> <pre><code>import re def trim_string(string): return re.sub(r'^([^0-9]+)(.*?)([^0-9]+)$', r'\2', string) </code></pre> <p>To break it down, the regex (<code>r'^([^0-9]+)(.*?)([^0-9]+)$'</code>) is like so:</p> <ul> <li><code>^</code> matches the start of a string.</li> <li><code>([^0-9]+)</code> matches a group of consecutive non-digit characters.</li> <li><code>(.*?)</code> matches a group of stuff (non-greedy).</li> <li><code>([^0-9]+)</code> matches another group of consecutive non-digit characters.</li> <li><code>$</code> matches the end of the string.</li> </ul> <p>The replacement string, <code>r'\2'</code>, just says to replace the matched string with only the second group, which is the stuff between the two groups of non-digit characters.</p> <hr> <p>But if you're <em>really</em> sure you want to use your existing solution, you need to understand how recursion actually works. When you call <code>return foo</code>, the function returns <code>foo</code> as its output. If you don't call <code>return</code>, you return <code>None</code> automatically.</p> <p>That being said, you need to <code>return</code> in every case of the recursion process, not just at the end:</p> <pre><code>def String_Trim(Raw_String): if Raw_String[0].isdigit() == False: New_String = Raw_String[1:] return String_Trim(New_String) elif Raw_String[-1].isdigit() == False: New_String = Raw_String[:-1] return String_Trim(New_String) else: print Raw_String return Raw_String </code></pre>

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