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copied!<p>Here's another way to go at it using dictionaries to group by sha and directory. This also gets rid of the random lists in the file names.</p> <pre><code>new_fail = {} # {sha: {dir: [filenames]}} for item in fail: # split data into it's parts sha, directory, filename = item # make sure the correct elements exist in the data structure if sha not in new_fail: new_fail[sha] = {} if directory not in new_fail[sha]: new_fail[sha][directory] = [] # this is where the lists are removed from the file names if type(filename) == type([]): filename = filename[0] new_fail[sha][directory].append(filename) diff = [] dup = [] # loop through the data, analyzing it for sha, val in new_fail.iteritems(): for directory, filenames in val.iteritems(): # check to see if the sha/dir combo has more than one file name if len(filenames) > 1: for filename in filenames: dup.append([sha, directory, filename]) else: diff.append([sha, dir, filenames[0]]) </code></pre> <p>To print it:</p> <pre><code>print 'diff:' for i in diff: print i print '\ndup:' for i in dup: print i </code></pre> <p>Sample data looks like this:</p> <pre> diff: ['da39a3ee5e6b4b0d3255bfef95601890afd80709', 'ron\\d', 'Sourcecheck.py'] ['da39a3ee5e6b4b0d3255bfef95601890afd80709', 'ron\\b\\include', 'Test.java'] ['da39a3ee5e6b4b0d3255bfef95601890afd80709', 'ron\\a\\include', 'svin.txt'] ['b5cc17d3a35877ca8b76f0b2e07497039c250696', 'ron\\a', 'apa2.txt'] ['b5cc17d3a35877ca8b76f0b2e07497039c250696', 'ron\\c', 'apa1.txt'] dup: ['95d1543adea47e88923c3d4ad56e9f65c2b40c76', 'ron\\c', 'knark.txt'] ['95d1543adea47e88923c3d4ad56e9f65c2b40c76', 'ron\\c', 'apa.txt']</pre>

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