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copied!<p>Well, my phone allows me to set which days are business days, but Windows/.NET won't, so I assume Monday through Friday.</p> <p>Note: As the question includes "golf" I am golfing this one, that is trying to use as few bytes for the script as possible. The code is not necessarily readable as a result.</p> <p>The easiest and most straightforward way to do is would be to start with today, add a day and look whether it is in the wanted range:</p> <pre><code>PS> $d = [DateTime]::Now.AddDays(1); while ($d.DayOfWeek -eq "Saturday" -or $d.DayOfWeek -eq "Sunday") { $d = $d.AddDays(1) }; $d Montag, 22. Juni 2009 19:50:27 </code></pre> <p>We can shorten that a little, though:</p> <pre><code>PS> $d=(Get-Date)+"1";for(;6,0-contains$d.DayOfWeek){$d+="1"}$d Montag, 22. Juni 2009 19:52:31 </code></pre> <p>But we can also try it differently, using the pipeline. The next business day is at least one and at most three days away, so we can generate a list of possible dates and filter them accordingly and at last, select the first one:</p> <pre><code>PS> @(1..3|%{(Get-Date).AddDays($_)}|?{$_.DayOfWeek -ge "Monday" -and $_.DayOfWeek -le "Friday"})[0] Montag, 22. Juni 2009 22:11:19 </code></pre> <p>or shorter:</p> <pre><code>PS> @(1..3|%{(Get-Date)+"$_"}|?{1..5-contains$_.DayOfWeek})[0] Montag, 22. Juni 2009 19:55:53 </code></pre> <p>By letting the range go to 4 we can guarantee that it always returns at least two workdays and save the @ operator to force an array:</p> <pre><code>PS> (1..4|%{(Get-Date)+"$_"}|?{1..5-contains$_.DayOfWeek})[0] Montag, 22. Juni 2009 20:24:06 </code></pre>

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