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    copied!<p>You should really use an xml parser to do this, but to answer your question:</p> <pre><code>import re def next_tag(s, tag): i = -1 while True: try: i = s.index(tag, i+1) except ValueError: return yield i a = "&lt;list&gt;&lt;list-item&gt;First level&lt;list&gt;&lt;list-item&gt;Second level&lt;/list-item&gt;&lt;/list&gt;&lt;/list-item&gt;&lt;/list&gt;" a = a.replace("&lt;list-item&gt;", "* ") for LEVEL, ind in enumerate(next_tag(a, "&lt;list&gt;")): a = re.sub("&lt;list&gt;", "\n" + LEVEL * "\t", a, 1) a = a.replace("&lt;/list-item&gt;", "") a = a.replace("&lt;/list&gt;", "") print a </code></pre> <p>This will work for your example, and <strong>your example ONLY</strong>. Use an XML parser. You can use <code>xml.dom.minidom</code> (it's included in Python (2.7 at least), no need to download anything):</p> <pre><code>import xml.dom.minidom def parseList(el, lvl=0): txt = "" indent = "\t" * (lvl) for item in el.childNodes: # These are the &lt;list-item&gt;s: They can have text and nested &lt;list&gt; tag for subitem in item.childNodes: if subitem.nodeType is xml.dom.minidom.Element.TEXT_NODE: # This is the text before the next &lt;list&gt; tag txt += "\n" + indent + "* " + subitem.nodeValue else: # This is the next list tag, its indent level is incremented txt += parseList(subitem, lvl=lvl+1) return txt def parseXML(s): doc = xml.dom.minidom.parseString(s) return parseList(doc.firstChild) a = "&lt;list&gt;&lt;list-item&gt;First level&lt;list&gt;&lt;list-item&gt;Second level&lt;/list-item&gt;&lt;list-item&gt;Second level 2&lt;list&gt;&lt;list-item&gt;Third level&lt;/list-item&gt;&lt;/list&gt;&lt;/list-item&gt;&lt;/list&gt;&lt;/list-item&gt;&lt;/list&gt;" print parseXML(a) </code></pre> <p>Output:</p> <pre><code>* First level * Second level * Second level 2 * Third level </code></pre>
 

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