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POMultiple radio button using php javascript ajax
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copied!<p>I am making a survey form with multiple radio buttons. the questions are in a database and i pick the questions and display options as radio buttons</p> <pre><code><div id="question"> <form id="pollform">; <?php $i=0; while(list($ID,$Question,$form,$one,$two,$three,$four,$five)=mysql_fetch_array($result)){ $i++; ?> <p><?php echo $ID.") ".$Question; ?></p> <input type="radio" name="radio<?php echo $i;?>" value="1" /> <?php echo $one; ?><br /> <input type="radio" name="radio<?php echo $i;?>" value="2" /> <?php echo $two; ?><br /> <input type="radio" name="radio<?php echo $i;?>" value="3" /> <?php echo $three; ?><br /> <input type="radio" name="radio<?php echo $i;?>" value="4" /> <?php echo $four; ?><br /> <input type="radio" name="radio<?php echo $i;?>" value="5" /> <?php echo $five; ?><br /> <?php } ?> <input type="button" id="review-submit" value="Submit" onclick="pollsubmit();"> <form> </div> </code></pre> <p>To process this and to send the selected answers using Ajax I used the following code </p> <pre><code><script language=Javascript> function pollsubmit(){ <?php $dbquerry="SELECT `ID`, `Question`, `Form`, `one`, `two`,`three`,`four`,`five` FROM `pollquestions` Order by `ID`"; $result=mysql_db_query($dbname,$dbquerry); ?> var answers = new Array(); var form1=document.getElementById("pollform"); <?php $count=0; while(list($ID,$Question,$form,$one,$two,$three,$four,$five)=mysql_fetch_array($result)){ $count++; ?> for (var i=1;i<=5;i++) { if(form1.radio<?php echo $count;?>[i].checked) { answers[<?echo $ID;?>]= form1.radio<?php echo $count;?>.value; } } <?php } ?> } </script> </code></pre> <p>But this is giving me an <code>Cannot read property 'checked' of undefined</code> though in both the places the name is radio1. whereas if i use only string say for example <code>name="radio1"</code> it is working but if i use <code>name="radio<?php echo $i;?>"</code> it is not working. Can you kindly help</p>

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