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PODynamic Type Creation with a Constructor that reference its dependencies
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  1. PODynamic Type Creation with a Constructor that reference its dependencies
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    copied!<p>I have the following classes:</p> <pre><code>public class Entity&lt;T&gt; where T : Entity&lt;T&gt; { public Factory&lt;T&gt; Factory { get; private set; } public Entity(Factory&lt;T&gt; factory) { Factory = factory; } } public class Factory&lt;T&gt; { } public class MyEntity : Entity&lt;MyEntity&gt; { public MyEntity(Factory&lt;MyEntity&gt; factory) : base(factory) { } } </code></pre> <p>I am trying to dynamically create class MyEntity with the constructor specified. So far I have the following code:</p> <pre><code>class Program { static ModuleBuilder _moduleBuilder; public static ModuleBuilder ModuleBuilder { get { if (_moduleBuilder == null) { AssemblyBuilder asmBuilder = System.Threading.Thread.GetDomain().DefineDynamicAssembly(new AssemblyName("Dynamic"), AssemblyBuilderAccess.Run); _moduleBuilder = asmBuilder.DefineDynamicModule("MainModule"); } return _moduleBuilder; } } static void Main(string[] args) { TypeBuilder typeBuilder = ModuleBuilder.DefineType("MyEntity", TypeAttributes.Public); Type baseType = typeof(Entity&lt;&gt;).MakeGenericType(typeBuilder); typeBuilder.SetParent(baseType); Type factoryType = typeof(Factory&lt;&gt;).MakeGenericType(typeBuilder); ConstructorBuilder cBuilder = typeBuilder.DefineConstructor(MethodAttributes.Public, CallingConventions.Standard, new Type[] { factoryType }); ILGenerator ctorIL = cBuilder.GetILGenerator(); ctorIL.Emit(OpCodes.Ldarg_0); ctorIL.Emit(OpCodes.Ldarg_1); ConstructorInfo c = baseType.GetConstructor(new Type[] { factoryType }); ctorIL.Emit(OpCodes.Call, c); ctorIL.Emit(OpCodes.Ret); Type syType = typeBuilder.CreateType(); Console.ReadLine(); } } </code></pre> <p>The code failed @ <code>ConstructorInfo c = baseType.GetConstructor(new Type[] { factoryType })</code>. I got a NotSupportedException.</p> <p>Is there any way to achieve this? I have been stonewalled by this for three days. Any help would be appreciated.</p> <p>Thanks!</p>
 

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